2=22/2f

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Solution for 2=22/2f equation: 



2=22/2f

We move all terms to the left:

2-(22/2f)=0



Domain of the equation: 2f)!=0

f!=0/1

f!=0

f∈R



We add all the numbers together, and all the variables

-(+22/2f)+2=0

We get rid of parentheses

-22/2f+2=0

We multiply all the terms by the denominator


2*2f-22=0

Wy multiply elements

4f-22=0

We move all terms containing f to the left, all other terms to the right

4f=22

f=22/4

f=5+1/2

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