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2=2/5(y-5)
We move all terms to the left:
2-(2/5(y-5))=0
Domain of the equation: 5(y-5))!=0We multiply all the terms by the denominator
y∈R
-(2+2*5(y-5))=0
We calculate terms in parentheses: -(2+2*5(y-5)), so:
2+2*5(y-5)
determiningTheFunctionDomain 2*5(y-5)+2
Wy multiply elements
10y(y+2
Back to the equation:
-(10y(y+2)
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10y(y+2
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10y(y+2
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10y(y+2
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10y(y+2
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10y(y+2
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10y(y+2
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10y(y+2
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10y(y+2
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