2=2(j+-4)

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Solution for 2=2(j+-4) equation: 



2=2(j+-4)

We move all terms to the left:

2-(2(j+-4))=0

We add all the numbers together, and all the variables

-(2(j-4))+2=0



We calculate terms in parentheses: -(2(j-4)), so:

2(j-4)

We multiply parentheses

2j-8

Back to the equation:

-(2j-8)



We get rid of parentheses

-2j+8+2=0

We add all the numbers together, and all the variables

-2j+10=0

We move all terms containing j to the left, all other terms to the right

-2j=-10

j=-10/-2

j=+5

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