2=2(b+1)-8

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Solution for 2=2(b+1)-8 equation: 



2=2(b+1)-8

We move all terms to the left:

2-(2(b+1)-8)=0



We calculate terms in parentheses: -(2(b+1)-8), so:

2(b+1)-8

We multiply parentheses

2b+2-8

We add all the numbers together, and all the variables

2b-6

Back to the equation:

-(2b-6)



We get rid of parentheses

-2b+6+2=0

We add all the numbers together, and all the variables

-2b+8=0

We move all terms containing b to the left, all other terms to the right

-2b=-8

b=-8/-2

b=+4

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