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2=11+3(x+)
We move all terms to the left:
2-(11+3(x+))=0
We add all the numbers together, and all the variables
-(11+3(+x))+2=0
We calculate terms in parentheses: -(11+3(+x)), so:We get rid of parentheses
11+3(+x)
determiningTheFunctionDomain 3(+x)+11
We multiply parentheses
3x+11
Back to the equation:
-(3x+11)
-3x-11+2=0
We add all the numbers together, and all the variables
-3x-9=0
We move all terms containing x to the left, all other terms to the right
-3x=9
x=9/-3
x=-3
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