2=11+29(m+3)

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Solution for 2=11+29(m+3) equation: 



2=11+29(m+3)

We move all terms to the left:

2-(11+29(m+3))=0



We calculate terms in parentheses: -(11+29(m+3)), so:

11+29(m+3)

determiningTheFunctionDomain
29(m+3)+11

We multiply parentheses

29m+87+11

We add all the numbers together, and all the variables

29m+98

Back to the equation:

-(29m+98)



We get rid of parentheses

-29m-98+2=0

We add all the numbers together, and all the variables

-29m-96=0

We move all terms containing m to the left, all other terms to the right

-29m=96

m=96/-29

m=-3+9/29

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