2=-4(3a+2)+13a

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Solution for 2=-4(3a+2)+13a equation: 



2=-4(3a+2)+13a

We move all terms to the left:

2-(-4(3a+2)+13a)=0



We calculate terms in parentheses: -(-4(3a+2)+13a), so:

-4(3a+2)+13a

We add all the numbers together, and all the variables

13a-4(3a+2)

We multiply parentheses

13a-12a-8

We add all the numbers together, and all the variables

a-8

Back to the equation:

-(a-8)



We get rid of parentheses

-a+8+2=0

We add all the numbers together, and all the variables

-1a+10=0

We move all terms containing a to the left, all other terms to the right

-a=-10

a=-10/-1

a=+10

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