2=-3/4(-3)+b

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Solution for 2=-3/4(-3)+b equation:



2=-3/4(-3)+b
We move all terms to the left:
2-(-3/4(-3)+b)=0
Domain of the equation: 4(-3)+b)!=0
b∈R
We multiply all the terms by the denominator
-(-3+2*4(-3)+b)=0
We calculate terms in parentheses: -(-3+2*4(-3)+b), so:
-3+2*4(-3)+b
determiningTheFunctionDomain b-3+2*4(-3)
We add all the numbers together, and all the variables
b-27
Back to the equation:
-(b-27)
We get rid of parentheses
-b+27=0
We add all the numbers together, and all the variables
-1b+27=0
We move all terms containing b to the left, all other terms to the right
-b=-27
b=-27/-1
b=+27

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