2=(n+3)/11

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Solution for 2=(n+3)/11 equation: 



2=(n+3)/11

We move all terms to the left:

2-((n+3)/11)=0

We multiply all the terms by the denominator


-((n+3)+2*11)=0



We calculate terms in parentheses: -((n+3)+2*11), so:

(n+3)+2*11

We add all the numbers together, and all the variables

(n+3)+22

We get rid of parentheses

n+3+22

We add all the numbers together, and all the variables

n+25

Back to the equation:

-(n+25)



We get rid of parentheses

-n-25=0

We add all the numbers together, and all the variables

-1n-25=0

We move all terms containing n to the left, all other terms to the right

-n=25

n=25/-1

n=-25

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