2=(c+3)/2

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Solution for 2=(c+3)/2 equation: 



2=(c+3)/2

We move all terms to the left:

2-((c+3)/2)=0

We multiply all the terms by the denominator


-((c+3)+2*2)=0



We calculate terms in parentheses: -((c+3)+2*2), so:

(c+3)+2*2

We add all the numbers together, and all the variables

(c+3)+4

We get rid of parentheses

c+3+4

We add all the numbers together, and all the variables

c+7

Back to the equation:

-(c+7)



We get rid of parentheses

-c-7=0

We add all the numbers together, and all the variables

-1c-7=0

We move all terms containing c to the left, all other terms to the right

-c=7

c=7/-1

c=-7

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