2=(4x+5)4=(x2-27)

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Solution for 2=(4x+5)4=(x2-27) equation: 



2=(4x+5)4=(x2-27)

We move all terms to the left:

2-((4x+5)4)=0



We calculate terms in parentheses: -((4x+5)4), so:

(4x+5)4

We multiply parentheses

16x+20

Back to the equation:

-(16x+20)



We get rid of parentheses

-16x-20+2=0

We add all the numbers together, and all the variables

-16x-18=0

We move all terms containing x to the left, all other terms to the right

-16x=18

x=18/-16

x=-1+1/8

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