2=(3x+19)/5

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Solution for 2=(3x+19)/5 equation: 



2=(3x+19)/5

We move all terms to the left:

2-((3x+19)/5)=0

We multiply all the terms by the denominator


-((3x+19)+2*5)=0



We calculate terms in parentheses: -((3x+19)+2*5), so:

(3x+19)+2*5

We add all the numbers together, and all the variables

(3x+19)+10

We get rid of parentheses

3x+19+10

We add all the numbers together, and all the variables

3x+29

Back to the equation:

-(3x+29)



We get rid of parentheses

-3x-29=0

We move all terms containing x to the left, all other terms to the right

-3x=29

x=29/-3

x=-9+2/3

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