2=(2+0)/(1-7)+b

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Solution for 2=(2+0)/(1-7)+b equation: 



2=(2+0)/(1-7)+b

We move all terms to the left:

2-((2+0)/(1-7)+b)=0



Domain of the equation: (1-7)+b)!=0

We move all terms containing b to the left, all other terms to the right

-7)+b!=-1

b!=-1/1

b!=-1

b∈R



We add all the numbers together, and all the variables

-(2/(-6)+b)+2=0

We multiply all the terms by the denominator


-(2+2*(-6)+b)=0



We calculate terms in parentheses: -(2+2*(-6)+b), so:

2+2*(-6)+b

determiningTheFunctionDomain
b+2+2*(-6)

We add all the numbers together, and all the variables

b-10

Back to the equation:

-(b-10)



We get rid of parentheses

-b+10=0

We add all the numbers together, and all the variables

-1b+10=0

We move all terms containing b to the left, all other terms to the right

-b=-10

b=-10/-1

b=+10

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