2=(10+z)/-3

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Solution for 2=(10+z)/-3 equation: 


z in (-oo:+oo)

2 = (z+10)/(-3) // - (z+10)/(-3)

2-((z+10)/(-3)) = 0

(-1*(z+10))/(-3)+2 = 0

(-1*(z+10))/(-3)+(-3*2)/(-3) = 0

-1*(z+10)-3*2 = 0

-z-16 = 0

(-z-16)/(-3) = 0

(-z-16)/(-3) = 0 // * -3

-z-16 = 0

-z-16 = 0 // + 16

-z = 16 // * -1

z = -16

z = -16

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