2=(1)/(3)z+5

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Solution for 2=(1)/(3)z+5 equation: 



2=(1)/(3)z+5

We move all terms to the left:

2-((1)/(3)z+5)=0



Domain of the equation: 3z+5)!=0

z∈R



We get rid of parentheses

-1/3z-5+2=0

We multiply all the terms by the denominator


-5*3z+2*3z-1=0

Wy multiply elements

-15z+6z-1=0

We add all the numbers together, and all the variables

-9z-1=0

We move all terms containing z to the left, all other terms to the right

-9z=1

z=1/-9

z=-1/9

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