29x+16-3(4x-6)=18+2(9x+1)+6-10x

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Solution for 29x+16-3(4x-6)=18+2(9x+1)+6-10x equation: 



29x+16-3(4x-6)=18+2(9x+1)+6-10x

We move all terms to the left:

29x+16-3(4x-6)-(18+2(9x+1)+6-10x)=0

We multiply parentheses

29x-12x-(18+2(9x+1)+6-10x)+18+16=0



We calculate terms in parentheses: -(18+2(9x+1)+6-10x), so:

18+2(9x+1)+6-10x

determiningTheFunctionDomain
2(9x+1)-10x+18+6

We add all the numbers together, and all the variables

-10x+2(9x+1)+24

We multiply parentheses

-10x+18x+2+24

We add all the numbers together, and all the variables

8x+26

Back to the equation:

-(8x+26)



We add all the numbers together, and all the variables

17x-(8x+26)+34=0

We get rid of parentheses

17x-8x-26+34=0

We add all the numbers together, and all the variables

9x+8=0

We move all terms containing x to the left, all other terms to the right

9x=-8

x=-8/9

x=-8/9

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