29=9-2(q-3)+4q

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Solution for 29=9-2(q-3)+4q equation: 



29=9-2(q-3)+4q

We move all terms to the left:

29-(9-2(q-3)+4q)=0



We calculate terms in parentheses: -(9-2(q-3)+4q), so:

9-2(q-3)+4q

determiningTheFunctionDomain
-2(q-3)+4q+9

We add all the numbers together, and all the variables

4q-2(q-3)+9

We multiply parentheses

4q-2q+6+9

We add all the numbers together, and all the variables

2q+15

Back to the equation:

-(2q+15)



We get rid of parentheses

-2q-15+29=0

We add all the numbers together, and all the variables

-2q+14=0

We move all terms containing q to the left, all other terms to the right

-2q=-14

q=-14/-2

q=+7

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