29=5v+2(v-3)

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Solution for 29=5v+2(v-3) equation: 



29=5v+2(v-3)

We move all terms to the left:

29-(5v+2(v-3))=0



We calculate terms in parentheses: -(5v+2(v-3)), so:

5v+2(v-3)

We multiply parentheses

5v+2v-6

We add all the numbers together, and all the variables

7v-6

Back to the equation:

-(7v-6)



We get rid of parentheses

-7v+6+29=0

We add all the numbers together, and all the variables

-7v+35=0

We move all terms containing v to the left, all other terms to the right

-7v=-35

v=-35/-7

v=+5

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