29=-6(1+b)-7(-2b+3)

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Solution for 29=-6(1+b)-7(-2b+3) equation: 



29=-6(1+b)-7(-2b+3)

We move all terms to the left:

29-(-6(1+b)-7(-2b+3))=0

We add all the numbers together, and all the variables

-(-6(b+1)-7(-2b+3))+29=0



We calculate terms in parentheses: -(-6(b+1)-7(-2b+3)), so:

-6(b+1)-7(-2b+3)

We multiply parentheses

-6b+14b-6-21

We add all the numbers together, and all the variables

8b-27

Back to the equation:

-(8b-27)



We get rid of parentheses

-8b+27+29=0

We add all the numbers together, and all the variables

-8b+56=0

We move all terms containing b to the left, all other terms to the right

-8b=-56

b=-56/-8

b=+7

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