29/5x=2x=

Solution for 29/5x=2x= equation:

29/5x=2x=

We move all terms to the left:

29/5x-(2x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

-2x+29/5x=0

We multiply all the terms by the denominator


-2x*5x+29=0

Wy multiply elements

-10x^2+29=0

a = -10; b = 0; c = +29;
Δ = b2-4ac
Δ = 02-4·(-10)·29
Δ = 1160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1160}=\sqrt{4*290}=\sqrt{4}*\sqrt{290}=2\sqrt{290}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{290}}{2*-10}=\frac{0-2\sqrt{290}}{-20}
=-\frac{2\sqrt{290}}{-20}
=-\frac{\sqrt{290}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{290}}{2*-10}=\frac{0+2\sqrt{290}}{-20}
=\frac{2\sqrt{290}}{-20}
=\frac{\sqrt{290}}{-10}
$