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28x^2=56
We move all terms to the left:
28x^2-(56)=0
a = 28; b = 0; c = -56;
Δ = b2-4ac
Δ = 02-4·28·(-56)
Δ = 6272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6272}=\sqrt{3136*2}=\sqrt{3136}*\sqrt{2}=56\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56\sqrt{2}}{2*28}=\frac{0-56\sqrt{2}}{56} =-\frac{56\sqrt{2}}{56} =-\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56\sqrt{2}}{2*28}=\frac{0+56\sqrt{2}}{56} =\frac{56\sqrt{2}}{56} =\sqrt{2} $
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