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28x^2+84x+56=0
a = 28; b = 84; c = +56;
Δ = b2-4ac
Δ = 842-4·28·56
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-28}{2*28}=\frac{-112}{56} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+28}{2*28}=\frac{-56}{56} =-1 $
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