28x-2(10+4x)=8x-2

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Solution for 28x-2(10+4x)=8x-2 equation: 



28x-2(10+4x)=8x-2

We move all terms to the left:

28x-2(10+4x)-(8x-2)=0

We add all the numbers together, and all the variables

28x-2(4x+10)-(8x-2)=0

We multiply parentheses

28x-8x-(8x-2)-20=0

We get rid of parentheses

28x-8x-8x+2-20=0

We add all the numbers together, and all the variables

12x-18=0

We move all terms containing x to the left, all other terms to the right

12x=18

x=18/12

x=1+1/2

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