28x-18-12x=4(4x-5)+2

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Solution for 28x-18-12x=4(4x-5)+2 equation: 



28x-18-12x=4(4x-5)+2

We move all terms to the left:

28x-18-12x-(4(4x-5)+2)=0

We add all the numbers together, and all the variables

16x-(4(4x-5)+2)-18=0



We calculate terms in parentheses: -(4(4x-5)+2), so:

4(4x-5)+2

We multiply parentheses

16x-20+2

We add all the numbers together, and all the variables

16x-18

Back to the equation:

-(16x-18)



We get rid of parentheses

16x-16x+18-18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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