28x+26=(x+3)(x-2)

Solution for 28x+26=(x+3)(x-2) equation:

28x+26=(x+3)(x-2)

We move all terms to the left:

28x+26-((x+3)(x-2))=0

We multiply parentheses ..

-((+x^2-2x+3x-6))+28x+26=0


We calculate terms in parentheses: -((+x^2-2x+3x-6)), so:

(+x^2-2x+3x-6)

We get rid of parentheses

x^2-2x+3x-6

We add all the numbers together, and all the variables

x^2+x-6

Back to the equation:

-(x^2+x-6)


We add all the numbers together, and all the variables

28x-(x^2+x-6)+26=0

We get rid of parentheses

-x^2+28x-x+6+26=0

We add all the numbers together, and all the variables

-1x^2+27x+32=0

a = -1; b = 27; c = +32;
Δ = b2-4ac
Δ = 272-4·(-1)·32
Δ = 857
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{857}}{2*-1}=\frac{-27-\sqrt{857}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{857}}{2*-1}=\frac{-27+\sqrt{857}}{-2}
$