28=j-12

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Solution for 28=j-12 equation: 



28=j-12

We move all terms to the left:

28-(j-12)=0

We get rid of parentheses

-j+12+28=0

We add all the numbers together, and all the variables

-1j+40=0

We move all terms containing j to the left, all other terms to the right

-j=-40

j=-40/-1

j=+40

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