28=4(v-3)+6v

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Solution for 28=4(v-3)+6v equation: 



28=4(v-3)+6v

We move all terms to the left:

28-(4(v-3)+6v)=0



We calculate terms in parentheses: -(4(v-3)+6v), so:

4(v-3)+6v

We add all the numbers together, and all the variables

6v+4(v-3)

We multiply parentheses

6v+4v-12

We add all the numbers together, and all the variables

10v-12

Back to the equation:

-(10v-12)



We get rid of parentheses

-10v+12+28=0

We add all the numbers together, and all the variables

-10v+40=0

We move all terms containing v to the left, all other terms to the right

-10v=-40

v=-40/-10

v=+4

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