28=3(u-4)+2u

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Solution for 28=3(u-4)+2u equation: 



28=3(u-4)+2u

We move all terms to the left:

28-(3(u-4)+2u)=0



We calculate terms in parentheses: -(3(u-4)+2u), so:

3(u-4)+2u

We add all the numbers together, and all the variables

2u+3(u-4)

We multiply parentheses

2u+3u-12

We add all the numbers together, and all the variables

5u-12

Back to the equation:

-(5u-12)



We get rid of parentheses

-5u+12+28=0

We add all the numbers together, and all the variables

-5u+40=0

We move all terms containing u to the left, all other terms to the right

-5u=-40

u=-40/-5

u=+8

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