28=29+3x-(1x-5)

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Solution for 28=29+3x-(1x-5) equation: 



28=29+3x-(1x-5)

We move all terms to the left:

28-(29+3x-(1x-5))=0

We add all the numbers together, and all the variables

-(29+3x-(x-5))+28=0



We calculate terms in parentheses: -(29+3x-(x-5)), so:

29+3x-(x-5)

determiningTheFunctionDomain
3x-(x-5)+29

We get rid of parentheses

3x-x+5+29

We add all the numbers together, and all the variables

2x+34

Back to the equation:

-(2x+34)



We get rid of parentheses

-2x-34+28=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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