28=2/5f

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Solution for 28=2/5f equation: 



28=2/5f

We move all terms to the left:

28-(2/5f)=0



Domain of the equation: 5f)!=0

f!=0/1

f!=0

f∈R



We add all the numbers together, and all the variables

-(+2/5f)+28=0

We get rid of parentheses

-2/5f+28=0

We multiply all the terms by the denominator


28*5f-2=0

Wy multiply elements

140f-2=0

We move all terms containing f to the left, all other terms to the right

140f=2

f=2/140

f=1/70

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