28=2(y+2)-5y

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Solution for 28=2(y+2)-5y equation: 



28=2(y+2)-5y

We move all terms to the left:

28-(2(y+2)-5y)=0



We calculate terms in parentheses: -(2(y+2)-5y), so:

2(y+2)-5y

We add all the numbers together, and all the variables

-5y+2(y+2)

We multiply parentheses

-5y+2y+4

We add all the numbers together, and all the variables

-3y+4

Back to the equation:

-(-3y+4)



We get rid of parentheses

3y-4+28=0

We add all the numbers together, and all the variables

3y+24=0

We move all terms containing y to the left, all other terms to the right

3y=-24

y=-24/3

y=-8

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