28=2(s-53)

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Solution for 28=2(s-53) equation: 



28=2(s-53)

We move all terms to the left:

28-(2(s-53))=0



We calculate terms in parentheses: -(2(s-53)), so:

2(s-53)

We multiply parentheses

2s-106

Back to the equation:

-(2s-106)



We get rid of parentheses

-2s+106+28=0

We add all the numbers together, and all the variables

-2s+134=0

We move all terms containing s to the left, all other terms to the right

-2s=-134

s=-134/-2

s=+67

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