28=-7(1+q)

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Solution for 28=-7(1+q) equation: 



28=-7(1+q)

We move all terms to the left:

28-(-7(1+q))=0

We add all the numbers together, and all the variables

-(-7(q+1))+28=0



We calculate terms in parentheses: -(-7(q+1)), so:

-7(q+1)

We multiply parentheses

-7q-7

Back to the equation:

-(-7q-7)



We get rid of parentheses

7q+7+28=0

We add all the numbers together, and all the variables

7q+35=0

We move all terms containing q to the left, all other terms to the right

7q=-35

q=-35/7

q=-5

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