28=-3(4z-2)

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Solution for 28=-3(4z-2) equation: 



28=-3(4z-2)

We move all terms to the left:

28-(-3(4z-2))=0



We calculate terms in parentheses: -(-3(4z-2)), so:

-3(4z-2)

We multiply parentheses

-12z+6

Back to the equation:

-(-12z+6)



We get rid of parentheses

12z-6+28=0

We add all the numbers together, and all the variables

12z+22=0

We move all terms containing z to the left, all other terms to the right

12z=-22

z=-22/12

z=-1+5/6

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