28=-2(3c+4)+12

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Solution for 28=-2(3c+4)+12 equation: 



28=-2(3c+4)+12

We move all terms to the left:

28-(-2(3c+4)+12)=0



We calculate terms in parentheses: -(-2(3c+4)+12), so:

-2(3c+4)+12

We multiply parentheses

-6c-8+12

We add all the numbers together, and all the variables

-6c+4

Back to the equation:

-(-6c+4)



We get rid of parentheses

6c-4+28=0

We add all the numbers together, and all the variables

6c+24=0

We move all terms containing c to the left, all other terms to the right

6c=-24

c=-24/6

c=-4

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