28=(w)(2w+1)

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Solution for 28=(w)(2w+1) equation:


Simplifying
28 = (w)(2w + 1)

Reorder the terms:
28 = w(1 + 2w)
28 = (1 * w + 2w * w)
28 = (1w + 2w2)

Solving
28 = 1w + 2w2

Solving for variable 'w'.

Reorder the terms:
28 + -1w + -2w2 = 1w + -1w + 2w2 + -2w2

Combine like terms: 1w + -1w = 0
28 + -1w + -2w2 = 0 + 2w2 + -2w2
28 + -1w + -2w2 = 2w2 + -2w2

Combine like terms: 2w2 + -2w2 = 0
28 + -1w + -2w2 = 0

Factor a trinomial.
(7 + -2w)(4 + w) = 0

Subproblem 1

Set the factor '(7 + -2w)' equal to zero and attempt to solve: Simplifying 7 + -2w = 0 Solving 7 + -2w = 0 Move all terms containing w to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -2w = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -2w = 0 + -7 -2w = 0 + -7 Combine like terms: 0 + -7 = -7 -2w = -7 Divide each side by '-2'. w = 3.5 Simplifying w = 3.5

Subproblem 2

Set the factor '(4 + w)' equal to zero and attempt to solve: Simplifying 4 + w = 0 Solving 4 + w = 0 Move all terms containing w to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + w = 0 + -4 Combine like terms: 4 + -4 = 0 0 + w = 0 + -4 w = 0 + -4 Combine like terms: 0 + -4 = -4 w = -4 Simplifying w = -4

Solution

w = {3.5, -4}

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