28=(7y-4)+y+5

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Solution for 28=(7y-4)+y+5 equation: 



28=(7y-4)+y+5

We move all terms to the left:

28-((7y-4)+y+5)=0



We calculate terms in parentheses: -((7y-4)+y+5), so:

(7y-4)+y+5

We add all the numbers together, and all the variables

y+(7y-4)+5

We get rid of parentheses

y+7y-4+5

We add all the numbers together, and all the variables

8y+1

Back to the equation:

-(8y+1)



We get rid of parentheses

-8y-1+28=0

We add all the numbers together, and all the variables

-8y+27=0

We move all terms containing y to the left, all other terms to the right

-8y=-27

y=-27/-8

y=3+3/8

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