288=(x/2)(x+(x*x))

Solution for 288=(x/2)(x+(x*x)) equation:

288=(x/2)(x+(x*x))

We move all terms to the left:

288-((x/2)(x+(x*x)))=0


Domain of the equation: 2)(x+(x*x)))!=0

x∈R


We add all the numbers together, and all the variables

-((+x/2)(x+(+x*x)))+288=0

We multiply all the terms by the denominator


-((+x+288*2)(x+(+x*x)))=0


We calculate terms in parentheses: -((+x+288*2)(x+(+x*x))), so:

(+x+288*2)(x+(+x*x))

We add all the numbers together, and all the variables

(x+576)(x+(+x*x))


We calculate terms in parentheses: +(x+576)(x+(+x*x)), so:

x+576)(x+(+x*x)

We get rid of parentheses

x+576)(x+x*x

Wy multiply elements

x^2+x+576)(x

Back to the equation:

+(x^2+x+576)(x)


We multiply parentheses

x^3+x^2+576x

We do not support expression: x^3