280=(2x)^2/(0.26-x)(0.26-x)

Solution for 280=(2x)^2/(0.26-x)(0.26-x) equation:

280=(2x)^2/(0.26-x)(0.26-x)

We move all terms to the left:

280-((2x)^2/(0.26-x)(0.26-x))=0


Domain of the equation: (0.26-x)(0.26-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.26-x)!=-0.26

x∈R


We add all the numbers together, and all the variables

-(2x^2/(-1x+0.26)(-1x+0.26))+280=0

We multiply parentheses ..

-(2x^2/(+x^2-0.26x-0.26x+0.0676))+280=0

We multiply all the terms by the denominator


-(2x^2+280*(+x^2-0.26x-0.26x+0.0676))=0


We calculate terms in parentheses: -(2x^2+280*(+x^2-0.26x-0.26x+0.0676)), so:

2x^2+280*(+x^2-0.26x-0.26x+0.0676)

We multiply parentheses

2x^2+280x^2+0x+0x+18.928

We add all the numbers together, and all the variables

282x^2+2x+18.928

Back to the equation:

-(282x^2+2x+18.928)


We get rid of parentheses

-282x^2-2x-18.928=0

a = -282; b = -2; c = -18.928;
Δ = b2-4ac
Δ = -22-4·(-282)·(-18.928)
Δ = -21346.784
Delta is less than zero, so there is no solution for the equation