28000(3000+1n)=36000(2000+1n)

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Solution for 28000(3000+1n)=36000(2000+1n) equation: 



28000(3000+1n)=36000(2000+1n)

We move all terms to the left:

28000(3000+1n)-(36000(2000+1n))=0

We add all the numbers together, and all the variables

28000(n+3000)-(36000(n+2000))=0

We multiply parentheses

28000n-(36000(n+2000))+84000000=0



We calculate terms in parentheses: -(36000(n+2000)), so:

36000(n+2000)

We multiply parentheses

36000n+72000000

Back to the equation:

-(36000n+72000000)



We get rid of parentheses

28000n-36000n-72000000+84000000=0

We add all the numbers together, and all the variables

-8000n+12000000=0

We move all terms containing n to the left, all other terms to the right

-8000n=-12000000

n=-12000000/-8000

n=+1500

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