28/(q-3)=7

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Solution for 28/(q-3)=7 equation: 


D( q )

q-3 = 0

q-3 = 0

q-3 = 0

q-3 = 0 // + 3

q = 3

q in (-oo:3) U (3:+oo)

28/(q-3) = 7 // - 7

28/(q-3)-7 = 0

28/(q-3)+(-7*(q-3))/(q-3) = 0

28-7*(q-3) = 0

49-7*q = 0

(49-7*q)/(q-3) = 0

(49-7*q)/(q-3) = 0 // * q-3

49-7*q = 0

49-7*q = 0 // - 49

-7*q = -49 // : -7

q = -49/(-7)

q = 7

q = 7

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