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28-x(17+3x)=60+2x
We move all terms to the left:
28-x(17+3x)-(60+2x)=0
We add all the numbers together, and all the variables
-x(3x+17)-(2x+60)+28=0
We multiply parentheses
-3x^2-17x-(2x+60)+28=0
We get rid of parentheses
-3x^2-17x-2x-60+28=0
We add all the numbers together, and all the variables
-3x^2-19x-32=0
a = -3; b = -19; c = -32;
Δ = b2-4ac
Δ = -192-4·(-3)·(-32)
Δ = -23
Delta is less than zero, so there is no solution for the equation
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