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28-5=2+3(x+5)
We move all terms to the left:
28-5-(2+3(x+5))=0
We add all the numbers together, and all the variables
-(2+3(x+5))+23=0
We calculate terms in parentheses: -(2+3(x+5)), so:We get rid of parentheses
2+3(x+5)
determiningTheFunctionDomain 3(x+5)+2
We multiply parentheses
3x+15+2
We add all the numbers together, and all the variables
3x+17
Back to the equation:
-(3x+17)
-3x-17+23=0
We add all the numbers together, and all the variables
-3x+6=0
We move all terms containing x to the left, all other terms to the right
-3x=-6
x=-6/-3
x=+2
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