28-5=2+3(3+x)

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Solution for 28-5=2+3(3+x) equation: 



28-5=2+3(3+x)

We move all terms to the left:

28-5-(2+3(3+x))=0

We add all the numbers together, and all the variables

-(2+3(x+3))+28-5=0

We add all the numbers together, and all the variables

-(2+3(x+3))+23=0



We calculate terms in parentheses: -(2+3(x+3)), so:

2+3(x+3)

determiningTheFunctionDomain
3(x+3)+2

We multiply parentheses

3x+9+2

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We get rid of parentheses

-3x-11+23=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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