28-5=2+(x+3)

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Solution for 28-5=2+(x+3) equation: 



28-5=2+(x+3)

We move all terms to the left:

28-5-(2+(x+3))=0

We add all the numbers together, and all the variables

-(2+(x+3))+23=0



We calculate terms in parentheses: -(2+(x+3)), so:

2+(x+3)

determiningTheFunctionDomain
(x+3)+2

We get rid of parentheses

x+3+2

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We get rid of parentheses

-x-5+23=0

We add all the numbers together, and all the variables

-1x+18=0

We move all terms containing x to the left, all other terms to the right

-x=-18

x=-18/-1

x=+18

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