28-(3y+4)=2(y+6)+y

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Solution for 28-(3y+4)=2(y+6)+y equation: 



28-(3y+4)=2(y+6)+y

We move all terms to the left:

28-(3y+4)-(2(y+6)+y)=0

We get rid of parentheses

-3y-(2(y+6)+y)-4+28=0



We calculate terms in parentheses: -(2(y+6)+y), so:

2(y+6)+y

We add all the numbers together, and all the variables

y+2(y+6)

We multiply parentheses

y+2y+12

We add all the numbers together, and all the variables

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

-3y-(3y+12)+24=0

We get rid of parentheses

-3y-3y-12+24=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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