28-(3c+4)=2(c+6)+6

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Solution for 28-(3c+4)=2(c+6)+6 equation:


Simplifying
28 + -1(3c + 4) = 2(c + 6) + 6

Reorder the terms:
28 + -1(4 + 3c) = 2(c + 6) + 6
28 + (4 * -1 + 3c * -1) = 2(c + 6) + 6
28 + (-4 + -3c) = 2(c + 6) + 6

Combine like terms: 28 + -4 = 24
24 + -3c = 2(c + 6) + 6

Reorder the terms:
24 + -3c = 2(6 + c) + 6
24 + -3c = (6 * 2 + c * 2) + 6
24 + -3c = (12 + 2c) + 6

Reorder the terms:
24 + -3c = 12 + 6 + 2c

Combine like terms: 12 + 6 = 18
24 + -3c = 18 + 2c

Solving
24 + -3c = 18 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
24 + -3c + -2c = 18 + 2c + -2c

Combine like terms: -3c + -2c = -5c
24 + -5c = 18 + 2c + -2c

Combine like terms: 2c + -2c = 0
24 + -5c = 18 + 0
24 + -5c = 18

Add '-24' to each side of the equation.
24 + -24 + -5c = 18 + -24

Combine like terms: 24 + -24 = 0
0 + -5c = 18 + -24
-5c = 18 + -24

Combine like terms: 18 + -24 = -6
-5c = -6

Divide each side by '-5'.
c = 1.2

Simplifying
c = 1.2

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