28-(3c+4)=2(c+6

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Solution for 28-(3c+4)=2(c+6 equation: 



28-(3c+4)=2(c+6

We move all terms to the left:

28-(3c+4)-(2(c+6)=0

We get rid of parentheses

-3c-(2(c+6)+28-4=0

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