28-(3/10)y=(7/10)y-12

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Solution for 28-(3/10)y=(7/10)y-12 equation: 


y in (-oo:+oo)

28-((3/10)*y) = (7/10)*y-12 // - (7/10)*y-12

12-((3/10)*y)-((7/10)*y)+28 = 0

(-3/10)*y+(-7/10)*y+12+28 = 0

40-y = 0 // - 40

-y = -40 // * -1

y = 40

y = 40

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