28-(2c+3)=3c+10

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Solution for 28-(2c+3)=3c+10 equation:


Simplifying
28 + -1(2c + 3) = 3c + 10

Reorder the terms:
28 + -1(3 + 2c) = 3c + 10
28 + (3 * -1 + 2c * -1) = 3c + 10
28 + (-3 + -2c) = 3c + 10

Combine like terms: 28 + -3 = 25
25 + -2c = 3c + 10

Reorder the terms:
25 + -2c = 10 + 3c

Solving
25 + -2c = 10 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
25 + -2c + -3c = 10 + 3c + -3c

Combine like terms: -2c + -3c = -5c
25 + -5c = 10 + 3c + -3c

Combine like terms: 3c + -3c = 0
25 + -5c = 10 + 0
25 + -5c = 10

Add '-25' to each side of the equation.
25 + -25 + -5c = 10 + -25

Combine like terms: 25 + -25 = 0
0 + -5c = 10 + -25
-5c = 10 + -25

Combine like terms: 10 + -25 = -15
-5c = -15

Divide each side by '-5'.
c = 3

Simplifying
c = 3

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